# Math Question

## One thought on “Math Question”

1. It’s 35.

$\begin{array}{l}{{\left( \frac{1}{4} \right)}^{18}}=\frac{1}{{{2}^{2(18)}}}=\frac{1}{{{2}^{36}}}\\{{\left( \frac{1}{5} \right)}^{m}}=\frac{1}{{{5}^{m}}}\\{{\left( \frac{1}{5} \right)}^{m}}{{\left( \frac{1}{4} \right)}^{18}}=\frac{1}{{{2}^{36}}\times {{5}^{m}}}=\frac{1}{2{{(10)}^{35}}}\\{{a}^{n}}{{b}^{n}}={{(ab)}^{n}}\\{{2}^{36}}={{2}^{35}}\times 2\\\frac{1}{2\times {{2}^{35}}\times {{5}^{m}}}=\frac{1}{2{{(10)}^{35}}}=\frac{1}{2\left( {{2}^{35}}\times {{5}^{35}} \right)}\\m=35\end{array}$

Hope that helps, sorry I didn’t see it before now – It’s a bit tricky to help blogs when you don’t see posts for months, haha!
If you need some more help, feel free to check out my blog, 🙂